The vapour pressurc at a given temperature of an ideal solution containing 0.2 mol of a non-volatile solute and 0.8 mol of solvent is 60 mm of Hg. The vapour pressure of the pure solvent at the same temperature is

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150 mm of Hg

75 mm of Hg

120 mm of Hg

60mm of Hg

answer is C.

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Detailed Solution

According to Raoult's law
$\frac{p^{\circ} - p}{p^{\circ}} = x_{B}$
[ x_B = Mole fraction of solute = $\frac{0 .2}{0 .2 + 0 .8} = \frac{1}{5}$
p =60 mm of Hg]
$\begin{array}{l} \frac{p^{\circ} - p}{p^{\circ}} = \frac{1}{5} or 4 p^{\circ} = (p) \times 5 \\ \Rightarrow p^{\circ} = \frac{60 \times 5}{4} = 75 mm of Hg \end{array}$

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