The vapour pressure of a pure liquid ‘A’ is 60mm, at 25°C. It forms an ideal solution with another liquid ‘B’. The mole fraction of ‘B’ is 0.6 and the total Pressure is 64mm. Then the vapour pressure of ‘B’ at 25°C is

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66.6

120

answer is B.

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Detailed Solution

$P_{t o t a l} = P_{A} X_{A} + P_{B} X_{B} 64 = 60 \times 0.4 + P_{B} \times 0.6 64 = 24 + P_{B} \times 0.6 40 = P_{B} \times 0.6 P_{B} = \frac{40}{0.6} = \frac{40 \times 10}{6} = \frac{200}{3} P_{B} = 66.6 m m$

Hence, the correct answer is 66.6mm.

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