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The vapour pressure of a solvent A is 0.8 atm. When a non-volatile substance B is added to this solvent its vapour pressure drops to 0.6 atm. What is mole fraction of B in solution

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0.75

0.25

0.50

0.90

answer is A.

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Detailed Solution

$\frac{P^{0} - P_{s}}{P^{0}} = X_{B}$

$\begin{array}{l} \frac{0.8 - 0.6}{0.8} = X_{B} \\ X_{B} = \frac{0.2}{0.8} = \frac{2}{8} = 0.25 \\ X_{B} = 0.25 \end{array}$

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