The vapour pressure of fluorobenzene at $t^{\circ }C$  is given by the equation.
$\text{log\hspace{0.17em}}P\left(mmHg\right)=7.0-\frac{1250}{t+220}$
Calculate the boiling point of the liquid in ${ }^{\circ }C$ if the external (applied) pressure is 5.26% more than required for normal boiling point. $(\log 2=0.3)$ .