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The vapour pressure of pure liquid A is 70 torr. At $27^{0} C$ . It forms an ideal solution with another liquid B. The mole fraction of B is 0.2 and total pressure of the solution is 84 torr at $27^{0} C$ . The vapour pressure of pure liquid B at $27^{0} C$ is

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14 torr

56 torr

140 torr

70 torr

answer is C.

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Detailed Solution

$P_{t o t a l} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B}$

$84 = 70 \times 0.8 + P_{B}^{0} \times 0.2$

$\frac{84 - 70 \times 0.8}{0.2} = P_{B}^{0}$

$P_{B}^{0} = 140 t o r r$

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