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Q.

The vapour pressure of pure A is 10 torr and at the same temperature when 1g of B is dissolved in 20 g of A, its vapour pressure is reduced to 9.0 torr. If the molecular mass of A is 200 amu, then the molecular mass of B is

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a

90amu

b

100amu

c

75amu

d

120amu

answer is B.

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Detailed Solution

 Po-PPo=Xs=nBnA+nB 10-910=1/MB20/200+1/MB On solving this, MB=90 amu .

Hence, the correct option (B). 90 amu .

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