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Q.

The vapour pressure of pure benzene at a certain temperature is 0.85 bar. A non-voltaile, non-electrolyte solid weighing 0.5g when added to 39.0g of benzene (molar mass 78g/mol) vapour pressure of the solution, then is 0.845 bar. What is the molar mass of the solid substance?

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answer is 170.

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Detailed Solution

$p_{1}^{0} = 0.85 b a r P^{s} = 0.845 b a r$

$M_{1} = 78 g / m o l$

$\frac{0.85 - 0.845}{0.85} = \frac{0.5 \times 78}{M_{2} \times 39}$

$M_{2} = 170 g / m o l$

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