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The vapour pressure of pure benzene is 640 mm at 298K. A solution of a solute in benzene shows a vapour pressure of 630 mm at the same temperature. Then the mole fraction of the solute is

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0.25

0.18

0.016

0.20

answer is A.

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Detailed Solution

Given: Vapor pressure of Benzene (p^∘)at 293K= 640mm

Vapor pressure of solution of Benzene at 293K(P)= 630mm

$\frac{P^{o} - P}{P^{o}} = X_{s} X_{s} = \frac{640 - 630}{640} = \frac{10}{640} = 0.016$

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