The vapour pressure of pure perfluoro cyclohexane (C6F12) are given by: Solid C6F12:log10P(mm of Hg)=8.68−1895TLiquid C6F12:log10P(mm of Hg)=7.60−1530TThe molar enthalpy of fusion of solid C6F12 is approximately x kJ, the value of x is

For solidlog P=logA−ΔHsub2.303R1T ΔHsub2.303R=1895For liquidlogP=logA−ΔHvap2.303R.1T ΔHvap2.303R=1530 ΔHfusion=ΔHsub−ΔHvap ΔHfusion=7KJ

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The vapour pressure of pure perfluoro cyclohexane $(C_{6} F_{12})$ are given by:
Solid $C_{6} F_{12} : \log_{10} P (m m o f H g) = 8.68 - \frac{1895}{T}$
Liquid $C_{6} F_{12} : \log_{10} P (m m o f H g) = 7.60 - \frac{1530}{T}$
The molar enthalpy of fusion of solid $C_{6} F_{12}$ is approximately x kJ, the value of x is

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Detailed Solution

For solid
$\log P = \log A - \frac{Δ H_{s u b}}{2.303 R} (\frac{1}{T}) \frac{Δ H_{s u b}}{2.303 R} = 1895$

For liquid
$\log P = \log A - \frac{Δ H_{v a p}}{2.303 R} . \frac{1}{T} \frac{Δ H_{v a p}}{2.303 R} = 1530 Δ H_{f u s i o n} = Δ H_{s u b} - Δ H_{v a p} Δ H_{f u s i o n} = 7 K J$