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The vapour pressure of water at 80°C is 355 mm of Hg. A 100mL vessel contains water saturated with O₂ at 80°C, the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50mL vessel at the same temperature. What is the partial pressure of O₂ ?

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405 mm

810 mm

1115 mm

355 mm

answer is B.

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Detailed Solution

volume of $O_{2} = 0.1 L$

$P_{O_{2}} = 760 - 355 = 405$ mm of Hg

Since the temperature is constant,
Using Boyle's law:

$P_{O_{2}} V_{O_{2}} = P_{O_{2}}^{'} V_{O_{2}}^{'}$

$405 \times 0.1 = P_{O_{2}}^{'} \times 0.05$

$P_{O_{2}}^{'} = \frac{405 \times 0.1}{0.05}$

$P_{O_{2}}^{'} = 810 mm$

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