The variance of first 50 even natural numbers is :

Variance of first ‘n’ even natural numbers is equal to

$$\begin{gathered} =\frac{{\mathrm{n}}^2-1}{12}{\mathrm{d}}^2=\frac{{\mathrm{n}}^2-1}{12}{2}^2=\frac{{50}^2-1}{3}\text{ where, }\mathrm{n}=50 , \\ and d= common difference=2; \\ \mathrm{Variance} \mathrm{of} 50 \mathrm{consecutive} \mathrm{even} \mathrm{natural} \mathrm{numbers}=833 \end{gathered}$$