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The variation of electric potential with distance 'r' from a fixed point is as shown in the figure. Electric intensity at r=1m, 3m and 5.5m are respectively (in v/m)

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–2, 1, 8/3

–2, 0, 8/3

2, 0, -8/3

+8, -1, -4/3

answer is B.

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Detailed Solution

$\begin{array}{l} E = - \frac{dV}{dr}; E_{1} = \frac{- (4 - 0)}{(2 - 0)} = - 2 \\ E_{2} = \frac{0}{1} = 0 (∵ V is constant); \\ E_{3} = - \frac{[0 - 4]}{1 .5} = \frac{8}{3} \end{array}$

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