The variation of g with height or depth (r) is shown correctly by the graph in figure (where R is the radius of the earth).

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Detailed Solution

Concept: We begin with the equation for g in relation to r from the earth's center with mass M and radius R, which is g=

\frac{GM}{r^{2}}

. Next, we discover the expression for g.
The magnitude of the earth's gravitational field, g, at a distance r from its center and mass M
The acceleration caused by gravity, which is defined as the force exerted on an object by the Earth's gravitational field, is known to be represented by the symbol g. The symbol representing this force is

F = mg

The object's mass, m, is indicated here. m=1 results in F=g.
This further confirms that g is the force acting on a mass unit. It is possible to precisely compute the g in a number of ways, and it is irrespective of the body's mass.
Now, we'll try to determine how g varies in relation to height h. Therefore, if we suppose that the item has mass M, the gravitational field intensity g at a distance r from the earth's center is given by:
gh at height h is determined by gh =