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Q.

The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement (x) starting from mean position to extreme position (A) is given by 

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a

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b

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c

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d

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answer is C.

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Detailed Solution

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KE=12mω2(A2−x2)  KE=12mω2A2−12mω2x2 y=k1−k2x2
The graph between KE and x will be
 

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