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The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is

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60 m

55 m

25 m

30 m

answer is B.

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Detailed Solution

Distance = Area under v – t graph

$= A_{1} + A_{2} + A_{3} + A_{4}$

$= \frac{1}{2} \times 1 \times 20 + (20 \times 1) + \frac{1}{2} (20 + 10) \times 1 + (10 \times 1)$ $= 10 + 20 + 15 + 10 = 55 m$

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