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The variation of volume V, with temperature T, keeping pressure constant is called the coefficient of thermal expansion ( $α$ ) = of a gas, i.e., $α = \frac{1}{V} {(\frac{\partial V}{\partial T})}_{p}$ . For an ideal gas $α$ is equal to

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1/P

1/T

answer is B.

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Detailed Solution

For n moles of an ideal gas, $PV = nRT$

$V = \frac{nRT}{P}$

Differentiating with respect to T at constant P, we have

${(\frac{\partial V}{\partial T})}_{P} = \frac{nR}{P} = \frac{V}{T}$

$α = \frac{1}{V} \times \frac{V}{T} = \frac{1}{T}$

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