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Q.

The vector equation of the line joining the points 3i +2j-4k , 5i +4 j -6k is

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a

r =(3i +2j-4k )+t(2i-2j-2k )

b

r =(3i +2j-4k )+t(-2i+2j-2k )

c

r =(3i +2j-4k )+t(2i+2j-2k )

d

r =(5i +4j-6k )+t(3i+2j-4k )

answer is A.

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Detailed Solution

r=a+y(b-a)  =(3i+2j-4k)+t(2i+2j-2k)

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