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Q.

The vector equation of the line passing through the point i¯-2j¯+k¯ and perpendicular to the vectors 2i¯-3j¯-k¯, i¯+4j¯-2k¯ is

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a

r¯=i¯+2j¯-k¯+t10i¯-3j¯-11k¯

b

r¯=i¯+2j¯-k¯+t10i¯+3j¯+11k¯

c

r¯=i¯+2j¯-k¯+t10i¯-3j¯+11k¯

d

r¯=i¯-2j¯+k¯+t10i¯+3j¯+11k¯

answer is A.

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Detailed Solution

a=i-2j+kb=2i-3j-k    c=i+4j-2kb×c=ijk2-3-114-2=i(10)-j(-3)+k(11)

eq of line passing through a and perpendicular to b, c  r=a+t(b×c)

r=(i-2j+k)+t(10i+3j+11k)

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