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Q.

 The vector equation of the plane passing through the line of intersection of two planes 

x2y+3z1=0,2x+y+z2=0 and passing through the point (1,2,3) is 

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a

r¯.i¯+3j¯2k¯1=0

b

r¯.i¯3j¯2k¯1=0

c

r¯.i¯+3j¯2k¯+1=0

d

r¯.i¯+3j¯2k¯3=0

answer is A.

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Detailed Solution

x2y+3z1+λ(2x+y+z2)=0 Substituting in above equation (1,2,3)14+91+λ(2+2+32)=05+5λ=0λ=1 Required equation x2y+3z12xyz+2=0x+3y2z1=0

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