The vector sum of three vectors A→,B→ and C→ is zero. If i^ and j^ are the unit vectors in the directions ofA→ and B→ respectively, then :

C → is in the plane of i ^ and j ^

C → is in the plane of i ^ and j ^

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The vector sum of three vectors $\vec{A}, \vec{B} and \vec{C}$ is zero. If $\hat{i} and \hat{j}$ are the unit vectors in the directions of $\vec{A} and \vec{B}$ respectively, then :

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\vec{C}

is in the plane of

\hat{i} and \hat{j}

\vec{C}

is along

\hat{i} \times \hat{j}

\vec{C}

is along

\hat{i}

\vec{C}

is along

\hat{j}

answer is A.

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Minimum number of coplanar vectors to get zero resultant is three. So if

\vec{A} + \vec{B} + \vec{C} = \vec{0},

, then

\vec{C}

must lie in same plane of

\vec{A} and \vec{B}

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