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Q.

The velocity and acceleration vectors of a particle undergoing circular motion are v=2i^m/s  and  a=2i^+4j^  m/s2  respectively at some instant of time. The radius of the circle is

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a

3 m

b

4 m

c

2 m

d

1 m

answer is A.

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Detailed Solution

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4j^ Component is perpendicular to velocity. So, it is radial (or normal) acceleration

       an=v2Ror        R=v2an=  (2)24=1m

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