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Q.

The velocity displacement (v-s) graph shown represents the motion of a particle moving along a straight line. The graph is a circle of radius 2 m and centre is at (2, 0) m.  
 

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 If the value of acceleration for this particle at a point  (2−2m,2ms−1) is  z ms−2, find z

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answer is 2.

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Detailed Solution

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(x−a)2+(y−b)2=r2           (s−2)2+(v−0)2=22⇒(s−2)2+v2=4        

Differentiating with respect to t,  

2(s−2)dsdt+2vdvdt=0        (s−2)+a =0                       {∴v=dsdt and a=dvdt}

At  s=(2−2)m,  (2−2)−2+a=0

So,  a=2 m/s2

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