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The velocity of a boat in still water is 10 m/s. If water flows in the river with a velocity of 6 m/s what is the difference in times taken to cross the river in the shortest path and the shortest time. The width of the river is 80 m.

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10s

$\frac{\sqrt{3}}{2}$ s

answer is D.

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Detailed Solution

$t_{1} = \frac{d}{\sqrt{V_{B}^{2} - V_{W}^{2}}} t_{2} = \frac{d}{V_{B}}$

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