The velocity of a body depends on time according to the equation $v= \frac{t^{ 2}}{10} + 20$. The body is undergoing

It is given that, $v= \frac{t^{ 2}}{10} + 20$

Differentiating both sides w.r.t. time, we get

$\frac{dv}{dt}=\frac{2t}{10}+0=\frac{t}{5}$

$\therefore$ Acceleration, $a =\frac{dv}{dt}=\frac{t}{5} \ne \mathrm{constant}$

Hence, it is a case of non-uniform acceleration.