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Q.

The velocity of a car at 10.50 a.m. is 40 km/h and at 10.52 a.m. it is 60 km/h. assuming constant acceleration in the given period, find its value.

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a

600 km/h2

b

200 km/h2

c

300 km/h2

d

400 km/h2

answer is D.

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Detailed Solution

Accelerations,

a=v-ut ⇒a=(60 km/h)-(40 km/h)2min=20 km/h130h ⇒a=600 km/h2

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