Q.

The velocity of a particle is v=v0+gt+ft2. If its position is x=0 at t=0, then its displacement after unit time t=1 is:

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a

v0+g2+f/3

b

v0+g2+f

c

v0+2g+3f

d

v0+g+f

answer is C.

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Detailed Solution

Given, velocity v=v0+gt+ft2v=dxdt or 0xdx=0tvdt

Or x=0tv0+gt+ft2dtx=v0t+gt22+ft33+C the constant of integration.

Given, x=0,t=0C=0 Or x=v0t+gt22+ft33 At t=1secx=v0+g2+f3

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