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The velocity of a particle moving in a straight line is proportional to the square root of the displacement then the particle moves with

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Variable acceleration

Constant acceleration

constant velocity

Acceleration proportional to the velocity

answer is B.

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Detailed Solution

$V α S^{2} V = {KS}^{2} \Rightarrow a = \frac{dv}{dt} = 2 KS \frac{ds}{dt} = 2 KS . ({KS}^{2}) = 2 K^{2} S^{3}$

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