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Q.

The velocity of a particle moving in the positive direction of x-axis varies as v=5x. Assuming that at t = 0, particle was at x = 0. Find the acceleration of particle.

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a

12.5 m/s2

b

7.5 m/s2

c

5 m/s2 

d

2.5 m/s2

answer is A.

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Detailed Solution

dvdx=52x Now, a=vdvdx=52x×5x=252=12.5 ms-2

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