The velocity of an electron in the first Bohr orbit of a hydrogen atom is $2.19 \times 10^{6} {ms}^{- 1}$ . Its velocity in the second orbit would be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$4.38 \times 10^{6} {ms}^{- 1}$

$8.76 \times 10^{6} {ms}^{- 1}$

$5.5 \times 10^{5} {ms}^{- 1}$

$1.10 \times 10^{6} {ms}^{- 1}$

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The expression of velocity is

$v = \frac{1}{n} (\frac{1}{2} \frac{Z e^{2}}{h ε_{0}})$ ;

Thus

$\frac{v_{2}}{v_{1}} = \frac{n_{1}}{n_{2}} \Rightarrow v = (2.19 \times 10^{6} {ms}^{- 1}) (\frac{1}{2}) = 1.10 \times 10^{6} {ms}^{- 1}$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test