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Q.

The velocity of sound in a gas, in which two wavelengths 4.08m and 4.16m produce 40 beats in 12sec, will be

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a

$282.8 m s^{- 1}$

b

$707.2 m s^{- 1}$

c

$353.6 m s^{- 1}$

d

$175.5 m s^{- 1}$

answer is D.

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Detailed Solution

$\begin{array}{l} Δ n = n_{1} - n_{2} = \frac{v}{λ_{1}} - \frac{v}{λ_{2}} \\ \frac{40}{12} = v (\frac{1}{4.08} - \frac{1}{4.16}) \\ v = 707.2 {ms}^{- 1} \end{array}$

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