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Q.

The velocity of sound waves in air is 330 m./sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6 π. The frequency of this wave is

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a

660 Hz

b

165 Hz

c

330 Hz

d

150 Hz

answer is C.

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Detailed Solution

Phase difference = 2πλ×Path difference

⇒1.6π = 2πλ×40  ⇒ λ = 50 cm = 0.5 m

⇒ v = nλ ⇒ 330 = 0.5×n    ⇒ n =660 Hz

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