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The velocity of sound waves in air is 330 m./sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6 $π$ . The frequency of this wave is

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660 Hz

165 Hz

330 Hz

150 Hz

answer is C.

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Detailed Solution

Phase difference = $\frac{2 π}{λ} \times Path difference$

$\Rightarrow 1.6 π = \frac{2 π}{λ} \times 40 \Rightarrow λ = 50 cm = 0.5 m$

$\Rightarrow v = nλ \Rightarrow 330 = 0.5 \times n \Rightarrow n = 660 Hz$

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