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The velocity time graph of a ball of mass 20 g moving along a straight line on a level ground is given below then the force that ground exert on the ball to bring it to rest is

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0.08 N

0.02 N

0.04 N

None of these

answer is A.

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Detailed Solution

$m = 20 g \Rightarrow \frac{20}{1000} kg, t = 10 s, v = 0 m / s, u = 20 m / s$
$\begin{array}{l} F = m \times \frac{(v - u)}{t} \\ F = \frac{20}{1000} \times \frac{(0 - 20)}{10} = - 0 .04 N, \end{array}$
Where –ve sign indicates opposing force

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