Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The velocity-time graph of a ball of mass 20 g moving along a straight line on a long table is given in the adjoining figure. How much force does the table exert on the ball to bring it to the rest?


Question Image

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

0.04 N

b

0.05 N

c

0.02 N

d

0.03 N 

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

According to the first law of motion:
F = m x a
=> F = m (v - u) / (t2 - t1)
On substituting the values, we get the force as
=> F = 0.02 (0 - 20) / (0 - 10)
=> F = 0.02 x 2
=> F = 0.04 N
 
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
The velocity-time graph of a ball of mass 20 g moving along a straight line on a long table is given in the adjoining figure. How much force does the table exert on the ball to bring it to the rest?