The velocity v of a particle at time t is given byv=at+bt+c,where a, b and c are constants. The dimensions of a, b and c are respectively

v=at+bt+c v=at LT-1=aT⇒a=LT-2 c=t ; bT=LT-1 c=T ;b=L

The velocity v of a particle at time t is given byv=at+bt+c,where a, b and c are constants. The dimensions of a, b and c are respectively

v=at+bt+c v=at LT-1=aT⇒a=LT-2 c=t ; bT=LT-1 c=T ;b=L

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The velocity v of a particle at time t is given by $v = a t + \frac{b}{t + c}$ ,where a, b and c are constants. The dimensions of a, b and c are respectively

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$[L T^{- 2}], [L] a n d [T]$

$[L^{2}], [T] a n d [L T^{- 2}]$

$[L T^{2}], [L T] a n d [L]$

$[L], [L T] a n d [T^{2}]$

answer is A.

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$v = a t + \frac{b}{t + c} v = a t [L T^{- 1}] = a [T] \Rightarrow a = [L T^{- 2}] c = t; \frac{b}{[T]} = [L T^{- 1}] c = [T]; b = [L]$

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The velocity v of a particle at time t is given byv=at+bt+c,where a, b and c are constants. The dimensions of a, b and c are respectively

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The velocity v of a particle at time t is given by $v = a t + \frac{b}{t + c}$ ,where a, b and c are constants. The dimensions of a, b and c are respectively