The vernier constant of a travelling microscope is 0.001 cm. If 49 main scale divisions coincide with 50 vernier scale divisions, then the value of 1 main scale division is

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0.5 mm

1 mm

0.4 mm

0.1 mm

answer is B.

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Detailed Solution

$\begin{array}{l} 50 VSD = 49 MSD \\ 1 VSD = \frac{49}{50} MSD \\ \Rightarrow VC = 1 MSD - 1 VSD \\ \Rightarrow VC = 1 MSD - \frac{49}{50} MSD \end{array} \begin{array}{l} \Rightarrow VC = \frac{1}{50} MSD \\ \Rightarrow 1 MSD = 50 (VC) = 50 (0 .001 cm) \\ \Rightarrow 1 MSD = 0 .05 cm = 0 .5 mm \\ \Rightarrow 1 MSD = 0 .5 mm \end{array}$

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