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The vernier constant of a vernier callipers is $0.001 cm$ . If $49$ main scale divisions coincide with $50$ vernier scale divisions, then the value of $1$ main scale division is

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0.1 mm

0.5 mm

0.4 mm

1 mm

answer is B.

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Detailed Solution

$50 VSD = 49 MSD$

$1 VSD = \frac{49}{50} MSD$

$V C = 1 MSD - 1 VSD$

$V C = 1 MSD - \frac{49}{50} MSD$

$V C = \frac{1}{50} M S D$

$1 MSD = 50 (VC)$

$= 50 (0.001 cm)$

$1 MSD = 0.5 mm$

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