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The Vernier scale of a travelling microscope has $50$ divisions which coincide with $49$ main scale divisions. If each main scale division is $0.5 mm$ , then the least count of the microscope is _____ mm.

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Detailed Solution

$1 MSD = 0.5 mm, 50 VSD = 49 MSD 1 VSD = \frac{49}{50} MSD$

Least count $= 1 MSD - 1 VSD$

$= 1 MSD - \frac{49}{50} MSD = \frac{1}{50} MSD = \frac{1}{50} \times 0.5 mm = 0.01 mm$

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