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Q.

The vertex and focus of a parabola are at a distance of h and k units on positive x–axis from origin. Then equation of parabola is

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a

y2=4(k-h) (x-h)

b

x-h2=4k-hy-k

c

y-k2=4k-hx-h

d

x2=4(k-h) (y-k)

answer is B.

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Detailed Solution

Let Focus =S, Vertex =V

Given that  OV=h,OS=k Vertex V=h,0 Distance between vertex and focus =a=k-h Now equation of parabola is  y2=4k-hx-h

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