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The vertical height of point $P$ above the ground is twice that of $Q$ . A particle is projected downward with a speed of $5 m / s$ from $P$ and at the same time another particle is projected upward with the same speed from $Q$ . Both particles reach the ground simultaneously, then

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$P Q = 30 m$

time of flight of stones $= 3 s$

Both $(1)$ and $(2)$ are correct

Both $(1)$ and $(2)$ are wrong

answer is C.

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Detailed Solution

$- h = 5 t - 5 t^{2}$
$- 2 h = - 5 t - 5 t^{2}$

The verical of point above the ground is twice that of Q. A particle is projected downward with a speed of 5 ms^(-1) from P and at the same time another particle

From these two equations,

we get, $t = 3 s$

and $h =$ distance between $P$

and $Q = 30 m$

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