The voltage across the $10 Ω$ resistor in the given circuit is x volt.
The value of ‘x’ to the nearest integer is __

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answer is 70.

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Detailed Solution

Here $R_{e q} = 10 + \frac{50 \times 20}{70} = \frac{170}{7} Ω$
So current through $10 Ω$ resistance $= \frac{E}{R_{e q}} = \frac{170}{\frac{170}{7}} = 7 A$
$∴ V_{R} = i R = 7 \times 10 = 70 V$

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