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The voltage E of a thermocouple as a function of temperature is given by $E = 6.2 T + 0.0002 T^{3}$ . When T changes from 100° to 101° the approximate change in E.

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12.12

12.1

12.2

answer is D.

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Detailed Solution

$\begin{array}{rcl} T & = & 100 αT = 1 \\ δE & = & 6.2 δT + 0.002 \times 3 T^{2} δT \\ = & 6.2 + 6 = 12.2 \end{array}$

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