The volume charge density of a sphere of radius 6 m is $2 μC {cm}^{- 3}$ . The number of lines of force per unit surface area coming out from the surface of the sphere is ______ $\times 10^{10} {NC}^{- 1}$ . [Given : Permittivity of vacuum $\in_{0} = 8 .85 \times 10^{- 12} C^{2} N^{- 1} - m^{- 2}$ ]

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is 45.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Number of lines of force per unit surface is nothing but Electric field at that point

$E = \frac{ρr}{3 ϵ_{0}}, for r = R$

$E = \frac{ρR}{3 ϵ_{0}} = \frac{2 \times 6}{3 \times 8.85 \times 10^{- 12}} = 0.45 \times 10^{12} {NC}^{- 1}$

$= 45 \times 10^{10} N / C$

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test