The volume contraction of a solid copper cube of edge length 10 cm, when subjected to a hydraulic pressure of 7 × 10⁶ Pa, would be _____ mm³. (Given bulk modulus of copper = 1.4 × 10¹¹ Nm^–2)

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answer is 50.

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Detailed Solution

$\begin{array}{l} B = \frac{ΔP}{\frac{ΔV}{V}} \\ ΔV = \frac{7 \times 10^{6}}{1.4 \times 10^{11}} \times {(10 \times 10^{- 2})}^{3} \\ ΔV = 50 {mm}^{3} \end{array}$

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