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The volume in litres of $C O_{2}$ liberated at STP, when 10g of 90% pure limestone is decomposed completely is

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2.016

20.16

2.24

22.4

answer is A.

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Detailed Solution

$C a C O_{3} \to C a O + C O_{2} \begin{array}{l} 100 g r \to 22.4 l i t \\ 10 g r \to ? \end{array} \frac{10}{100} \times 22.4 = 2.24 l i t \begin{array}{l} 100 \to 2.24 \\ 90 \to ? \\ \frac{90}{100} \times 2.24 = 2.016 \end{array}$

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