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The Volume (in Lts.) of $C O_{2}$ liberated at STP, when 10gms of 90% pure lime stone is heated completely.

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$2.016$

$20.16$

$2.24$

$22.4$

answer is A.

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Detailed Solution

$C a C O_{3} \to C a o + C O_{2}$
$100 g m \to 22.4 l t o f C O_{2} a t S T P$
$10 \times \frac{90}{100} = 9 g m \to ?$
$\frac{9 \times 22.4}{100} = 2.016 L t a t S T P$

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