The volume, in $mL$, of $0.02M{K}_2{Cr}_2{O}_7$ solution required to react with $0.288 g$ of ferrous oxalate in acidic medium is ____.

$\left( \right.$Molar mass of $\left.Fe=56 g{ mol}^{-1}\right)$

$K_2{\stackrel{+6}{Cr}}_2{O}_7+{\stackrel{+2}{Fe}C}_2{O}_4⟶{Cr}^{+3}+{Fe}^{+3}+{CO}_2$

${\left(\mathrm{VM}\times \mathrm{n}-\mathrm{factor}\right)}_{{\mathrm{KMnO}}_4}={\left(\frac{\mathrm{Wt}.}{\mathrm{E}}\right)}_{{\mathrm{FeC}}_2{\mathrm{O}}_4}$

$\frac{0.02\times 6\times V\left(mL\right)}{1000}=\frac{0.288}{144/3}$

Solving this, Volume is obtained as 50ml.

Hence the correct answer is 50.