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The volume occupied by 1.8 g of water vapor at 374°C and 1 bar pressure will be : [Use R = 0.083 bar L K^-1mol^-1]

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3.10 L

96.66 L

55.87 L

5.37 L

answer is A.

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Detailed Solution

$\begin{array}{l} PV = nRT \\ V = \frac{w}{M} (\frac{RT}{P}) \\ V = \frac{1 .8}{18} \times \frac{0 .083 \times 647}{1} = 5 .37 L \end{array}$

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