The volume occupied by the molecules contained in 4.5 kg water at STP, if the intermolecular forces vanish away is :

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$5.6 \times 10^{6} m^{3}$

$5 .6 \times 10^{3} m^{3}$

$5 .6 m^{3}$

$5.6 \times 10^{- 3} m^{3}$

answer is C.

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Detailed Solution

Each mole will occupy $22 .4 \times 10^{- 3} m^{3}$
No. of moles $= \frac{4500}{18}$
Volume $= 22 .4 \times 10^{- 3} \times \frac{4500}{18} = 5 .6 m^{3}$

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