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The volume of a frustum of a cone of height h and ends radii $r_{1}$ and $r_{2}$ is

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\frac{1}{3} π h (r_{1}^{2} + r_{2}^{2} + r_{1} r_{2})

\frac{1}{3} π h (r_{1}^{2} + r_{2}^{2} - r_{1} r_{2})

\frac{1}{2} π h (r_{1}^{2} + r_{2}^{2} - r_{1} r_{2})

π h (r_{1}^{2} + r_{2}^{2} + r_{1} r_{2})

answer is A.

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Detailed Solution

Given,
A frustum of a cone of height h and ends radii

r_{1}

and

r_{2}

.
As we know,
Volume of a frustum of a cone =

\frac{1}{3} π h (R_{1}^{2} + R_{2}^{2} + R_{1} R_{2})

Therefore, volume of a frustum of a cone of height h and ends radii

r_{1}

and

r_{2}

,
⇒

\frac{1}{3} π h (r_{1}^{2} + r_{2}^{2} + r_{1} r_{2})

Hence, the correct option is 1.

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