The volume of a solid is 3500 cc under atmospheric pressure. The change in its volume n×10-4cc, when subjected to a pressure of 25 atmosphere. The value of n is Bulk modulus of solid =1011 N/m2 1 atm=105 N/m2

B=-△PVΔV⇒ΔV=-△PVK=25×105×35001011=0.0875cc=875×10-4cc

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The volume of a solid is 3500 cc under atmospheric pressure. The change in its volume $n \times 10^{- 4} cc$ , when subjected to a pressure of 25 atmosphere. The value of n is
Bulk modulus of solid $= 10^{11} N / m^{2} (1 atm = 10^{5} N / m^{2})$

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answer is 875.

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$B = \frac{- △ PV}{ΔV}$

$\Rightarrow ΔV = - \frac{△ PV}{K} = \frac{25 \times 10^{5} \times 3500}{10^{11}} = 0 .0875 cc = 875 \times 10^{- 4} cc$

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